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Author Topic: math help  (Read 3511 times)

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greenkoolayd

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math help
« on: January 20, 2010, 02:43:23 pm »
5006=1000(1.01)12n

i cant remember how to get to the next step.  im solving for n.

(SFBL-sorry for being lame)
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AugustWest

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Re: math help
« Reply #1 on: January 20, 2010, 02:57:48 pm »
5006 = 1000(1.01)12 (1.01)n

5006/1000(1.01)12 = (1.01)n


Does that help?
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greenkoolayd

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Re: math help
« Reply #2 on: January 20, 2010, 03:12:22 pm »
frigg yeah.
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miles

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Re: math help
« Reply #3 on: January 21, 2010, 01:21:33 am »
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oball

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Re: math help
« Reply #4 on: January 21, 2010, 02:45:31 am »
Yep.

5006 = 1000(1.01)12 (1.01)n would be the case if the original equation were 5006 = 1000(1.01)12+n

In this case you want 5006 = 1000((1.0112)n)

Which would be 5.006 = ~1.127n

I think.
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bluemoon72

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Re: math help
« Reply #5 on: January 21, 2010, 04:01:41 am »
CCWW.
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AugustWest

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Re: math help
« Reply #6 on: January 21, 2010, 04:59:40 am »
Quote from: oball on January 21, 2010, 02:45:31 am
Yep.

5006 = 1000(1.01)12 (1.01)n would be the case if the original equation were 5006 = 1000(1.01)12+n

In this case you want 5006 = 1000((1.0112)n)

Which would be 5.006 = ~1.127n

I think.

You guys are exactly right and I realized my error earlier this evening.  Sorry dude.  Wish I'd caught it before everybody else did.
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Thomas Pain

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Re: math help
« Reply #7 on: January 21, 2010, 05:01:17 am »
5006=1000(1.01)^(12n)

like... um

5006^(1/12)= 1000(1.01)^n   right?  something like that... I'm a tryn' to express 12 root or some such

(5006^(1/12))^(1/n)= 1000(1.01)

(whatever)^(1/n)= wutuvu       (too lazy to do the math on those.  who the fnck cares anyway ,right?

(whatever)^(1/n)= wutuvu      and then from here, it's something to do with that thing where recipricoals in exponentials can magically move to somewhere else if reciprocolated...  I forget the details exactly but if you're reading this then you probably know what I mean.
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miles

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Re: math help
« Reply #8 on: January 21, 2010, 05:07:37 am »
Quote from: AugustWest on January 21, 2010, 04:59:40 am
You guys are exactly right and I realized my error earlier this evening.  Sorry dude.  Wish I'd caught it before everybody else did.

Ah, umm, yes. I hope I didn't make it seem like I was saying "that doesn't help because it is incorrect." What I meant to say is "NO WAY THAT SHIT'S INSANE, IT'S ALL CHING CHONG WING WONG"

I don't want to give the impression I would be able to to correct an error in a math problem. But good job Oball.
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oball

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Re: math help
« Reply #9 on: January 21, 2010, 06:03:48 am »
To be fair I can't remember any of that stuff and I had to look up the exponent rules on Wikipedia.
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KeithHernandez

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Re: math help
« Reply #10 on: January 21, 2010, 06:06:51 am »
Shit, when I was in college we looked up our own half assed info on wikipedia.

and we liked it
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AugustWest

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Re: math help
« Reply #11 on: January 21, 2010, 02:31:08 pm »
Quote from: KeithHernandez on January 21, 2010, 06:06:51 am
Shit, when I was in college we looked up our own half assed info on wikipedia.

and we liked it

Hell, when I was in college we just wrote a letter to Leibniz and asked him for crib notes.
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Re: math help
« Reply #12 on: January 22, 2010, 06:29:41 pm »
Quote from: AugustWest on January 21, 2010, 02:31:08 pm
Hell, when I was in college we just wrote a letter to Leibniz and asked him for crib notes.

Hey, it worked for Newton.

jk, as it were.
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